document.write( "Question 1197139: Find the total amount that must be repaid on the following note described.
\n" );
document.write( "$8,593 borrowed at 14.5% simple interest
\n" );
document.write( "What is the total amount to be repaid 3 years, 125 days later? (Round answer to the nearest cent.) \n" );
document.write( "
Algebra.Com's Answer #830263 by Theo(13342)![]() ![]() You can put this solution on YOUR website! simple interest formula is: \n" ); document.write( "i = p * r * n \n" ); document.write( "i is the interest \n" ); document.write( "p is the principal \n" ); document.write( "r is the interest rate per time period. \n" ); document.write( "n is the number of time periods.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the principal = 8593. \n" ); document.write( "the interest rate = 14.5% per year = .145 \n" ); document.write( "the number of time periods is 3 years and 125 days. \n" ); document.write( "normally a 365 day year is assumed. \n" ); document.write( "125 days is therefore 125 / 365 years. \n" ); document.write( "the number of time periods is therefore 3 + (125/365) years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula becomes: \n" ); document.write( "i = 8593 * .145 * (3 + 125/365) = 4164.662192\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add that to the principal to get 8593 + 4164.66 = 12757.66 is owed at the end of the loan period. \n" ); document.write( " |