document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=114089>Question 114089</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A deposit of $1000 is made into a fund with an annual interest rate of 10%. Find the time(in years) necessary for the investment to double if the interest is compounded continuously.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #83025 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=83025\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A deposit of $1000 is made into a fund with an annual interest rate of 10%. Find the time(in years) necessary for the investment to double if the interest is compounded continuously. <BR>\n" );
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document.write( "2000 = 1000e^(0.10*t)<BR>\n" );
document.write( "2 = e^(0.10t)<BR>\n" );
document.write( "Take the natural log to get:<BR>\n" );
document.write( "ln2 = 0.10t<BR>\n" );
document.write( "t = [ln2]/0.10<BR>\n" );
document.write( "t = 6.9 years<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );