document.write( "Question 1197083: 2. First-semester GPA’s for a random selection of freshmen at a large university are shown below. Estimate the true mean GPA of the frshman class with 99% confidence. Assume standard deviation = 0.62.
\n" ); document.write( "1.9 3.2 2.0 2.9 2.7 3.3
\n" ); document.write( "2.8 3.0 3.8 2.7 2.0 1.9
\n" ); document.write( "2.5 2.7 2.8 3.2 3.0 3.8
\n" ); document.write( "3.1 2.7 3.5 3.8 3.9 2.7
\n" ); document.write( "2.0 2.8 1.9 4.0 2.2 2.8
\n" ); document.write( "2.1 2.4 3.0 3.4 2.9 2.1
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Algebra.Com's Answer #830179 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Enter the given data into a spreadsheet.
\n" ); document.write( "Let's say the upper left corner is in cell A1
\n" ); document.write( "That places the bottom right corner in cell F6\r
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\n" ); document.write( "\n" ); document.write( "In another blank cell off to the side somewhere, type in =AVERAGE(A1:F6) to find the arithmetic mean of this data set.
\n" ); document.write( "Don't forget about the equal sign up front.
\n" ); document.write( "The result should be roughly 2.819444
\n" ); document.write( "This is the sample mean xbar.\r
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\n" ); document.write( "\n" ); document.write( "If you wanted to find the value of xbar another way, then add up all the values and divide by 36 since there are 6*6 = 36 items in this list.
\n" ); document.write( "The values add up to 101.5 which leads to xbar = 101.5/36 = 2.819444
\n" ); document.write( "The command =SUM(A1:F6) will add up the values in cells A1 to F6.\r
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\n" ); document.write( "\n" ); document.write( "At 99% confidence, the z critical value is roughly z = 2.576
\n" ); document.write( "Use a table like this
\n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf
\n" ); document.write( "to get that value. Look at the bottom row labeled \"Z\" and above the 99% confidence level.\r
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\n" ); document.write( "\n" ); document.write( "An alternative way to calculate this critical value is to type =NORMINV((1-0.99)/2, 0, 1) into the spreadsheet.
\n" ); document.write( "The portion (1-0.99)/2 represents the area in each tail at 99% confidence.
\n" ); document.write( "The spreadsheet should display -2.5758293035489, but we'll go with the positive version of that number.\r
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\n" ); document.write( "\n" ); document.write( "We have this information
\n" ); document.write( "z = 2.576 = critical value
\n" ); document.write( "xbar = 2.819444 = approximate sample mean
\n" ); document.write( "sigma = 0.62 = given population standard deviation
\n" ); document.write( "n = 36 = sample size\r
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\n" ); document.write( "\n" ); document.write( "Let's compute the margin of error
\n" ); document.write( "E = z*sigma/sqrt(n)
\n" ); document.write( "E = 2.576*0.62/sqrt(36)
\n" ); document.write( "E = 0.266187\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "L = lower boundary
\n" ); document.write( "L = xbar - E
\n" ); document.write( "L = 2.819444 - 0.266187
\n" ); document.write( "L = 2.553257
\n" ); document.write( "L = 2.55
\n" ); document.write( "and
\n" ); document.write( "U = upper boundary
\n" ); document.write( "U = xbar + E
\n" ); document.write( "U = 2.819444 + 0.266187
\n" ); document.write( "U = 3.085631
\n" ); document.write( "U = 3.09\r
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\n" ); document.write( "\n" ); document.write( "The 99% confidence interval for the population mean mu is roughly (2.55, 3.09)
\n" ); document.write( "This is in the format (L, U)\r
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\n" ); document.write( "\n" ); document.write( "This can be expressed as 2.55 < mu < 3.09 which is in the format L < mu < U\r
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\n" ); document.write( "\n" ); document.write( "A third alternative is to say \"2.819444+%2B-++0.266187\" which is in the format \"xbar+%2B-+E\"\r
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\n" ); document.write( "\n" ); document.write( "Round each value according to the instructions your teacher provides.
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