document.write( "Question 1196931: in kindergarten,12% of the students are Malays and the rest are Chinese.50% of the Chinese and 12.5% of the Malays are boys.There are 912 more Chinese than Malay students.how many girls are there in kindergarten? \n" ); document.write( "

Algebra.Com's Answer #830178 by MathTherapy(10552) $\"\"$ $\"About$

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in kindergarten,12% of the students are Malays and the rest are Chinese.50% of the Chinese and 12.5% of the Malays are boys.There are 912 more Chinese than Malay students.how many girls are there in kindergarten?
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You don't need all those variables that the other person used. They only make the problem more complex and are more\r\n" );
document.write( "likely to lead to errors.\r\n" );
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document.write( "Given that 12% are Malays, 88% are Chinese. \r\n" );
document.write( "Let number of students be S\r\n" );
document.write( "Given that there are 912 more Chinese than Malays, we get: .88S = .12S + 912\r\n" );
document.write( ".88S - .12S = 912\r\n" );
document.write( ".76S = 912\r\n" );
document.write( "Number of students or  \r\n" );
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document.write( "With 12.5% of Malays being boys, then 87.5% of Malays, or 10.5% (87.5% of 12%) are girls.\r\n" );
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document.write( "Likewise, with 50% of Chinese being boys, then 50% of Chinese, or 44% (50% of 88%) are girls.\r\n" );
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document.write( "Therefore, percent of girls in the kindergarten = 10.5 + 44 = 54.5%, or .545\r\n" );
document.write( "Number of girls in the kindergarten = .545(1,200) = 654.\r\n" );
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document.write( "You can also create a chart if it makes things clearer and easier.

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