document.write( "Question 114039: A father is four times as old as his daughter. In 6 years, he will be three times as old as she is. How old is the daughter now? \n" ); document.write( "
Algebra.Com's Answer #83016 by checkley71(8403)\"\" \"About 
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LET THE FATHER'S AGE=4X & HIS DAUGHTER'S AGE=X.
\n" ); document.write( "4X+6=3(X+6)
\n" ); document.write( "4X+6=3X+18
\n" ); document.write( "4X-3X=18-6
\n" ); document.write( "X=12 YEARS OLD IS THE DAUGHTERS AGE NOW.
\n" ); document.write( "PROOF
\n" ); document.write( "4*12+6=3(12+6)
\n" ); document.write( "48+6=3*18
\n" ); document.write( "54=54\r
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