document.write( "Question 114039: A father is four times as old as his daughter. In 6 years, he will be three times as old as she is. How old is the daughter now? \n" ); document.write( "
Algebra.Com's Answer #83016 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! LET THE FATHER'S AGE=4X & HIS DAUGHTER'S AGE=X. \n" ); document.write( "4X+6=3(X+6) \n" ); document.write( "4X+6=3X+18 \n" ); document.write( "4X-3X=18-6 \n" ); document.write( "X=12 YEARS OLD IS THE DAUGHTERS AGE NOW. \n" ); document.write( "PROOF \n" ); document.write( "4*12+6=3(12+6) \n" ); document.write( "48+6=3*18 \n" ); document.write( "54=54\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |