document.write( "Question 1197053: The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 315 grams and a standard deviation of 16 grams. Find the weight that corresponds to each event. (Round your final answer to 2 decimal places.)\r
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Algebra.Com's Answer #830152 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi  \r\n" );
document.write( "Recommend the use of a calculator and understanding of the  standard normal curve \r\n" );
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document.write( "Normal Distribution:  µ = 0 and σ = 1\r\n" );
document.write( "z score represents the area under the curve to the LEFT of its value\r\n" );
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document.write( "Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus\r\n" );
document.write( "Calculator function Invnorm(X) gives value to the LEFT of z\r\n" );
document.write( "Middle 60%    |z= Invnorm(20%) = -.84 (to 2 decimal places)\r\n" );
document.write( "Middle 60%:   -.84 to .84\r\n" );
document.write( "|\"blue%2816%29%2A%28-.84%29+%2B+315+=+blue+%28314.46%29\" \r\n" );
document.write( "|\"blue%2816%29%2A.84+%2B+315+=+blue+%28328.44%29\" \r\n" );
document.write( "weight from:  314.46 to 328.44\r\n" );
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document.write( "Highest 80 percent:  weight > 314.46\r\n" );
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document.write( "Lowest 15 percent:   |z= Invnorm(15%) = -1.04  |\"blue%2816%29%2A%28-1.04%29+%2B+315+=+blue+%28298.36%29\"  weight ≤ 298.36\r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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