document.write( "Question 1197054: Tire pressure monitoring systems (TPMS) warn the driver when the tire pressure of the vehicle is 28% below the target pressure. Suppose the target tire pressure of a certain car is 32 psi (pounds per square inch.)
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document.write( "a)At what psi will the TPMS trigger a warnig for this car? (Round your answer to 2 decimal points.)\r
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document.write( "b)Suppose tire pressure is a normally distributed random variable with a standard deviation equal to 3 psi. If the car's average tire pressure is on target, what is the probability that the TPMS will trigger a warning? (Round your answer to 4 decimal places.)\r
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document.write( "c)The manufacturer's recommended correct inflation range is 30 psi to 34 psi. Assume the tire's average psi is on target. If a tire on the car is inspected at random, what is the probability that the tire's inflation is within the recomended range? (Round your intermediate calculations and final answer to 4 decimal places.) \n" );
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Algebra.Com's Answer #830149 by Theo(13342)![]() ![]() You can put this solution on YOUR website! a)At what psi will the TPMS trigger a warnig for this car? (Round your answer to 2 decimal points.)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "target pressure = 32 psi. \n" ); document.write( "28% below 32 = (1 - .28) * 32 = 23.04 psi. \n" ); document.write( "when the target pressure gets below that, the tpms will warn the driver.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b)Suppose tire pressure is a normally distributed random variable with a standard deviation equal to 3 psi. If the car's average tire pressure is on target, what is the probability that the TPMS will trigger a warning? (Round your answer to 4 decimal places.)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with a mean of 32 and a standard deviation of 3, the probability that the tpms will trigger a warning will be based on the following formula. \n" ); document.write( "z = (x - m) / s \n" ); document.write( "z is the z-score \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard deviation. \n" ); document.write( "when x = 23.04 and m = 32 and s = 3, the formula becomes: \n" ); document.write( "z = (23.04 - 32) / 3 = -2.9867 rounded to 4 decimal places. \n" ); document.write( "probability of getting a z-score less than that is equal to .0014.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c)The manufacturer's recommended correct inflation range is 30 psi to 34 psi. Assume the tire's average psi is on target. If a tire on the car is inspected at random, what is the probability that the tire's inflation is within the recommended range? (Round your intermediate calculations and final answer to 4 decimal places.)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z-score for psi of 30: \n" ); document.write( "z = (30 - 32) / 3 = -.6667 rounded to 4 decimal places. \n" ); document.write( "z-score for psi of 45: \n" ); document.write( "z = (34 - 32) / 3 = .6667 rounded to 4 decimal places. \n" ); document.write( "probability of getting a z-score less than -.6667 is equal to .2525 rounded to 4 decimal places. \n" ); document.write( "probability of getting a z-score less than .6667 is equal to .7475 rounded to 4 decimal places. \n" ); document.write( "probability of getting a z-score between -.6667 and .6667 is equal to .7475 minus .2524 = .4950.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |