document.write( "Question 1197045: Find three consecutive positive integers which have 110 as the sum of their squares. \n" ); document.write( "
Algebra.Com's Answer #830129 by ikleyn(52864)\"\" \"About 
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\n" ); document.write( "Find three consecutive positive integers which have 110 as the sum of their squares.
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document.write( "(x-1)^2 + x^2 + (x+1)^2 = 110\r\n" );
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document.write( "(x^2 - 2x + 1) + x^2 + (x^2 + 2x + 1) = 110\r\n" );
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document.write( "3x^2 + 2 = 110\r\n" );
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document.write( "   3x^2  = 110 - 2 = 108\r\n" );
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document.write( "    x^2            = 108/3 = 36\r\n" );
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document.write( "    x                      = \"sqrt%2836%29\" = 6.\r\n" );
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document.write( "ANSWER.  The numbers are 5, 6 and 7.\r\n" );
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document.write( "CHECK.  25 + 36 + 49 = 110.    ! correct !\r\n" );
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