document.write( "Question 17066: Really, expressions involving variables, subtraction: I am trying to solve \"3y=6x%2B21+and+3y=-4x%2B31\" by subtraction instead of graphing. I have tried 6x+21minus-4x+31 and came up with 2x + -10 which doesn't work for the problem. How would I find he constant for the variables? What steps do I take to solve it correctly? Thank you for the help! \n" ); document.write( "
Algebra.Com's Answer #8301 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
If as you say, \"3y=6x%2B21\" and \"3y=-4x%2B31\", then
\n" ); document.write( "3y = 3y, so
\n" ); document.write( "6x+21 = -4x + 31\r
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\n" ); document.write( "\n" ); document.write( "It would be a nice idea to solve this equation for x, by adding +4x to each side:
\n" ); document.write( "6x + 4x + 21 = -4x + 4x + 31
\n" ); document.write( "10x + 21 = 31\r
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\n" ); document.write( "\n" ); document.write( "Next, subtract 21 from each side:
\n" ); document.write( "10x + 21 - 21 = 31 - 21
\n" ); document.write( "10x = 10
\n" ); document.write( "x= 1\r
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\n" ); document.write( "\n" ); document.write( "Solve for y next:
\n" ); document.write( "3y = 6x + 21
\n" ); document.write( "3y = 6(1) + 21
\n" ); document.write( "3y = 27
\n" ); document.write( "y= 9\r
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\n" ); document.write( "\n" ); document.write( "Solution (1, 9).\r
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\n" ); document.write( "\n" ); document.write( "Check: Use the other equation.
\n" ); document.write( "3y = -4x + 31
\n" ); document.write( "3(9) = -4(1) + 31
\n" ); document.write( "27 = 27
\n" ); document.write( "It checks!!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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