document.write( "Question 1196998: A cone-shaped paper drinking cup is to hold 40cm^3 of water. Find the height and radius of the cup that will require the least amount of paper. NOTE: Enter the exact answers. \n" ); document.write( "
Algebra.Com's Answer #830090 by ikleyn(52800)\"\" \"About 
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\n" ); document.write( "A cone-shaped paper drinking cup is to hold 40cm^3 of water.
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\n" ); document.write( "\n" ); document.write( "            The  \"solution\"  by  @ewatrrr is  INCORRECT.\r
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\n" ); document.write( "\n" ); document.write( "            It is incorrect,  since she uses the formula for the total surface area of the cone, \r
\n" ); document.write( "\n" ); document.write( "            including its base,  while in this problem the area of the base of the cone should  NOT  be included\r
\n" ); document.write( "\n" ); document.write( "            and should not be considered,  at all.\r
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\n" ); document.write( "\n" ); document.write( "            So,  I came to bring a correct solution.\r
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document.write( "The volume of the cone cup is given 40 cm^3.\r\n" );
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document.write( "The lateral area of a cone is\r\n" );
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document.write( "    S = \"pi%2Ar%2As\",       (1)\r\n" );
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document.write( "where r is the base radius and \"s\" is the slant height:  s = \"sqrt%28h%5E2+%2B+r%5E2%29\".\r\n" );
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document.write( "So, we need minimize the lateral area\r\n" );
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document.write( "    S = \"pi%2Ar%2Asqrt%28h%5E2%2Br%5E2%29\"    (2)\r\n" );
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document.write( "at given restriction for the volume\r\n" );
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document.write( "    \"%281%2F3%29%2Api%2Ar%5E2%2Ah\" = 40  cm^3.    (3)\r\n" );
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document.write( "From the restriction (3),   \r\n" );
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document.write( "    h = \"120%2F%28pi%2Ar%5E2%29\". \r\n" );
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document.write( "We substitute it into expression (2), and we get S(r) as a function of the radius r, only\r\n" );
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document.write( "    S(r) = \"pi%2Ar%2Asqrt%28%2814400%2F%28pi%5E2%2Ar%5E4%29%29+%2B+r%5E2%29\" = \"sqrt%28%2814400%2Fr%5E2%29+%2B+pi%5E2%2Ar%5E4%29\"\r\n" );
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document.write( "    +-------------------------------------------------------+\r\n" );
document.write( "    |    To find the minimum of S(r), we should calculate   |\r\n" );
document.write( "    |         the derivative and equate it to zero.         |\r\n" );
document.write( "    +-------------------------------------------------------+\r\n" );
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document.write( "I will not calculate the derivative in full, which is a complicated fraction. \r\n" );
document.write( "It is enough to calculate its numerator and equate it to zero. It gives this equation\r\n" );
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document.write( "    -\"2%2A%2814400%2Fr%5E3%29\" + \"4%2Api%5E2r%5E3\" = 0,\r\n" );
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document.write( "or, equivalently\r\n" );
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document.write( "    7200 = \"pi%5E2%2Ar%5E6\",   \"r%5E6\" = \"7200%2Fpi%5E2\",   r = \"root%286%2C7200%2Fpi%5E2%29\" = 3.0 cm.    (4)\r\n" );
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document.write( "So, the radius is just found.  The height should be  \r\n" );
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document.write( "    h = \"120%2F%28pi%2Ar%5E2%29\" = \"120%2F%28pi%2A3%5E2%29\" = 4.24 cm.    (5)\r\n" );
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document.write( "Expressions (4) and (5) give the required exact formulas and approximate numerical values.\r\n" );
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\n" ); document.write( "\n" ); document.write( "For your safety,  ignore the post by @ewatrrr,  since her solution is incorrect.\r
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\n" ); document.write( "\n" ); document.write( "From day to day,  this woman repeats the same error:  she tries to solve problems that are out of her competency.\r
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