document.write( "Question 1196953: The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 405 grams and a standard deviation of 21 grams. Find the weight that corresponds to each event. (Use Excel or Appendix C to calculate the z-value. Round your final answers to 2 decimal places.)\r
\n" ); document.write( "\n" ); document.write( "Middle 60 percent_____to_____
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Algebra.Com's Answer #830058 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i used the ti-84 plus.
\n" ); document.write( "middle 60 percent has area between z-score = -.8416212335 and z-score = .8416212335
\n" ); document.write( "round to 3 decimal places to get from z-score -.842 to .842
\n" ); document.write( "highest 80 percent has area to the right of z-score = -.8416212335
\n" ); document.write( "round to 3 decimal places to get area to the right of z-score = -.842
\n" ); document.write( "lowest 15 percent has area to the left of z-score = - 1.03643330
\n" ); document.write( "round to 3 decimal places to get area to the left of z-score = -1.036
\n" ); document.write( "i confirmed these results were accurate using the online normal distribution calculator at https://davidmlane.com/hyperstat/z_table.html.
\n" ); document.write( "here are the results from using that calculator.
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\n" ); document.write( "the commands you would use with excel and the result of using those commands is shown below.
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\n" ); document.write( "normsinv() gets you the z-score that has the specified area to the left of it.
\n" ); document.write( "normsdist() gets you the area to the left of the specified z-score.
\n" ); document.write( "to get the z-scores that has have an area of .6 between them, you would do the following.
\n" ); document.write( "find the area to the left and right of .6.
\n" ); document.write( "since the whole area is 1, then .2 is the area to the left of .6 and .2 is the area to the right of .6 because .2 + .6 + .2 = 1
\n" ); document.write( "the low z-score will have an area of .2 to the left of it.
\n" ); document.write( "the high z-score will have an area of .8 to the left of it.
\n" ); document.write( "the .8 to the left of the high z-score contains .2 + .6 = .8
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