document.write( "Question 1196995: The manager of a garden shop mixes grass seed that is 30% rye grass with 56 lb of grass seed that is 75% rye grass to make a mixture that is 65% rye grass. How much of the 30% rye grass is used? \r
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Algebra.Com's Answer #830053 by Theo(13342)\"\" \"About 
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let x = amount of grass that is 30% rye.
\n" ); document.write( "56 = amount of grass that is 75% rye.
\n" ); document.write( "x + 56 = amount of grass that is 65% rye.
\n" ); document.write( "you get:
\n" ); document.write( ".3 * x + .75 * 56 = .65 * (x + 56)
\n" ); document.write( "simplify to get:
\n" ); document.write( ".3 * x + 42 = .65 * x + 36.4
\n" ); document.write( "subtract .3 * x from both sides of the equation and subtract 36.4 from both sides of the equation to get:
\n" ); document.write( "42 - 36.4 = .65 * x - .3 * x
\n" ); document.write( "simplify to get:
\n" ); document.write( "5.6 = .35 * x
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 5.6 / .35 = 16
\n" ); document.write( "your solution is that 16 pounds of the 30% rye grass is used.\r
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