document.write( "Question 1196948: A ship traveling east at 30 mph is 10 mi from a harbor when another ship leaves the harbor traveling east at 40 mph. How long does it take the second ship to catch up to the first ship?
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Algebra.Com's Answer #830031 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The distance the second ship needs to make up is 10 miles; the rate of catching up is the difference between the two speeds, which is 40-30 = 10mph.

\n" ); document.write( "I assume you are familiar with the basic formula

\n" ); document.write( "time = distance / rate

\n" ); document.write( "It is similarly true that

\n" ); document.write( "time = (difference in distances) / (difference in rates)

\n" ); document.write( "So the number of hours required for the second ship to catch up to the first is 10/10 = 1.

\n" ); document.write( "ANSWER: 1 hour

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