document.write( "Question 1196971: How many liters of a blue dye that costs $1.90 per liter must be mixed with 22 L of anil that costs $2.50 per liter to make a mixture that costs $2.10 per liter? \r
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Algebra.Com's Answer #830027 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "First a typical formal algebraic solution....

\n" ); document.write( "x liters at $1.90 per liter, plus 22 liters at $2.50 per liter, yields (x+22) liters at $2.10 per liter:

\n" ); document.write( "\"x%281.90%29%2B22%282.50%29=%28x%2B22%29%282.10%29\"
\n" ); document.write( "\"1.90x%2B55=2.10x%2B46.20\"
\n" ); document.write( "\"8.80=0.20x\"
\n" ); document.write( "\"x=8.80%2F0.20=44\"

\n" ); document.write( "ANSWER: 44 liters

\n" ); document.write( "And then a quick and easy informal solution, if formal algebra is not required....

\n" ); document.write( "Look at the three prices per liter -- $1.90, $2.10, and $2.50 -- (on a number line, if it helps) and observe/calculate that $2.10 is 1/3 of the way from $1.90 to $2.50.

\n" ); document.write( "That means 1/3 of the mixture needs to be the more expensive ingredient -- i.e., there needs to be twice as much of the less expensive ingredient.

\n" ); document.write( "Since there are 22 liters of the more expensive ingredient, there need to be 2*22 = 44 liters of the less expensive.

\n" ); document.write( "ANSWER (again, of course): 44 liters

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