document.write( "Question 1196971: How many liters of a blue dye that costs $1.90 per liter must be mixed with 22 L of anil that costs $2.50 per liter to make a mixture that costs $2.10 per liter? \r
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Algebra.Com's Answer #830027 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First a typical formal algebraic solution.... \n" ); document.write( "x liters at $1.90 per liter, plus 22 liters at $2.50 per liter, yields (x+22) liters at $2.10 per liter: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: 44 liters \n" ); document.write( "And then a quick and easy informal solution, if formal algebra is not required.... \n" ); document.write( "Look at the three prices per liter -- $1.90, $2.10, and $2.50 -- (on a number line, if it helps) and observe/calculate that $2.10 is 1/3 of the way from $1.90 to $2.50. \n" ); document.write( "That means 1/3 of the mixture needs to be the more expensive ingredient -- i.e., there needs to be twice as much of the less expensive ingredient. \n" ); document.write( "Since there are 22 liters of the more expensive ingredient, there need to be 2*22 = 44 liters of the less expensive. \n" ); document.write( "ANSWER (again, of course): 44 liters \n" ); document.write( " \n" ); document.write( " |