document.write( "Question 1196959: Makana invested $500 in a simple interest account that had an interest rate that was 1% more than that of her friend Marlys. If Marlys earned $27 after one year from an investment of $450, how much did Makana earn in one year?\r
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Algebra.Com's Answer #830000 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Makana invested at the rate x (decimal) per year.\r\n" );
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document.write( "Marlys invested at the rate (x-0.01) per year.\r\n" );
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document.write( "Write equation for the Marlys interest\r\n" );
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document.write( "   450*(x-0.01) = 27.\r\n" );
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document.write( "From this equation\r\n" );
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document.write( "    x - 0.01 =  = 0.06.\r\n" );
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document.write( "Thus, the Marlys rate is 0.06, or 6% per year.\r\n" );
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document.write( "Hence, the Makana rate is 0.07, or 7% per year.\r\n" );
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document.write( "It means that Makana earns 0.07*500 = 35 dollars in a year from his/(her) investment of $500.    ANSWER\r\n" );
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