document.write( "Question 114061: Ok, I have been trying to solve this problem for a while. The problem is (6x-4)^2=40. The directions say to solve, and I have foiled the quanity and tried to factor, I have tried to take the square roots, and I can't seem to figure it out.
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document.write( "The problem is - (6x-4)^2=40\r
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document.write( "Please help.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #82997 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! (6X-4)^2=40 \n" ); document.write( "36X^2-48X+16-40=0 \n" ); document.write( "36X^2-48X-24=0 \n" ); document.write( "12(3X^2-4X-2)=0 \n" ); document.write( "USING THE QUADRATIC EQUATION WE GET: \n" ); document.write( " \n" ); document.write( "X=(4+-SQRT[(4^2-4*3*-2])/2*3 \n" ); document.write( "X=(4+-SQRT[16+24)/6 \n" ); document.write( "X=(4+-SQRT40)/6 \n" ); document.write( "X=(4+-6.32)/6 \n" ); document.write( "X=(4+6.32)/6 \n" ); document.write( "X=10.32/6 \n" ); document.write( "X=1.72 ANSWER \n" ); document.write( "X=(4-6.32)/6 \n" ); document.write( "X=-2.32/6 \n" ); document.write( "X=-0.39 ANSWER. \n" ); document.write( " |