document.write( "Question 1196891: Assume that one adult with smart phones are renewly selected 41% use them in meetings or class. If 6 adult smartphone users are randomly selected find the probability that at least 4 of them use their smart phone in meetings or classes. \n" ); document.write( "
Algebra.Com's Answer #829936 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "When I searched out part of your problem, I came across this exact wording \"Assume that when adults with smartphones are randomly selected, 51% use them in meetings or classes. If 6 adult smartphone users are randomly selected, find the probability that exactly 4 of them use their smartphones in meetings or classes.\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll assume that your problem fits a similar format.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Question: \n" ); document.write( "Assume that when adults with smartphones are randomly selected, 41% use them in meetings or classes. If 6 adult smartphone users are randomly selected find the probability that at least 4 of them use their smart phone in meetings or classes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solution: \n" ); document.write( "n = 6 = sample size \n" ); document.write( "p = 0.41 = probability someone uses a smartphone in meetings or in class\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's consider the case where exactly x = 4 people use a smartphone during meetings or in class \n" ); document.write( "Use the nCr combination formula to find that 6C4 = 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The scratch work is shown below \n" ); document.write( "n C r = (n!)/(r!(n-r)!) \n" ); document.write( "6 C 4 = (6!)/(4!*(6-4)!) \n" ); document.write( "6 C 4 = (6!)/(4!*2!) \n" ); document.write( "6 C 4 = (6*5*4!)/(4!*2!) \n" ); document.write( "6 C 4 = (6*5)/(2!) \n" ); document.write( "6 C 4 = (6*5)/(2*1) \n" ); document.write( "6 C 4 = (30)/(2) \n" ); document.write( "6 C 4 = 15 \n" ); document.write( "There are 15 ways to select four from a pool of six, where order doesn't matter. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then use the binomial distribution formula \n" ); document.write( "P(x) = (n C x)*(p)^(x)*(1-p)^(n-x) \n" ); document.write( "P(4) = (6 C 4)*(0.41)^(4)*(1-0.41)^(6-4) \n" ); document.write( "P(4) = (6 C 4)*(0.41)^(4)*(0.59)^(2) \n" ); document.write( "P(4) = (15)*(0.41)^(4)*(0.59)^2 \n" ); document.write( "P(4) = (15)*(0.02825761)*(0.3481) \n" ); document.write( "P(4) = 0.147547110615 \n" ); document.write( "The probability that exactly 4 people use their phone during meetings or in class is roughly 0.147547110615\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Repeat similar steps for x = 5 and x = 6 \n" ); document.write( "I'll skip the steps and jump to the results of each \n" ); document.write( "P(5) = 0.041013095154 \n" ); document.write( "P(6) = 0.004750104241\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The probability of at least 4 people, out of 6 total in the sample size, using a smartphone during meetings or class is roughly 0.19331031001 \n" ); document.write( "When rounding to something like four decimal places, we get roughly 0.1933 \n" ); document.write( "Round the answer however your teacher instructs. \n" ); document.write( " \n" ); document.write( " |