document.write( "Question 1196891: Assume that one adult with smart phones are renewly selected 41% use them in meetings or class. If 6 adult smartphone users are randomly selected find the probability that at least 4 of them use their smart phone in meetings or classes. \n" ); document.write( "
Algebra.Com's Answer #829936 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "When I searched out part of your problem, I came across this exact wording \"Assume that when adults with smartphones are randomly selected, 51% use them in meetings or classes. If 6 adult smartphone users are randomly selected, find the probability that exactly 4 of them use their smartphones in meetings or classes.\"\r
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\n" ); document.write( "\n" ); document.write( "I'll assume that your problem fits a similar format.\r
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\n" ); document.write( "\n" ); document.write( "Question:
\n" ); document.write( "Assume that when adults with smartphones are randomly selected, 41% use them in meetings or classes. If 6 adult smartphone users are randomly selected find the probability that at least 4 of them use their smart phone in meetings or classes.\r
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\n" ); document.write( "\n" ); document.write( "Solution:
\n" ); document.write( "n = 6 = sample size
\n" ); document.write( "p = 0.41 = probability someone uses a smartphone in meetings or in class\r
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\n" ); document.write( "\n" ); document.write( "Let's consider the case where exactly x = 4 people use a smartphone during meetings or in class
\n" ); document.write( "Use the nCr combination formula to find that 6C4 = 15\r
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\n" ); document.write( "\n" ); document.write( "The scratch work is shown below
\n" ); document.write( "n C r = (n!)/(r!(n-r)!)
\n" ); document.write( "6 C 4 = (6!)/(4!*(6-4)!)
\n" ); document.write( "6 C 4 = (6!)/(4!*2!)
\n" ); document.write( "6 C 4 = (6*5*4!)/(4!*2!)
\n" ); document.write( "6 C 4 = (6*5)/(2!)
\n" ); document.write( "6 C 4 = (6*5)/(2*1)
\n" ); document.write( "6 C 4 = (30)/(2)
\n" ); document.write( "6 C 4 = 15
\n" ); document.write( "There are 15 ways to select four from a pool of six, where order doesn't matter. \r
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\n" ); document.write( "\n" ); document.write( "Then use the binomial distribution formula
\n" ); document.write( "P(x) = (n C x)*(p)^(x)*(1-p)^(n-x)
\n" ); document.write( "P(4) = (6 C 4)*(0.41)^(4)*(1-0.41)^(6-4)
\n" ); document.write( "P(4) = (6 C 4)*(0.41)^(4)*(0.59)^(2)
\n" ); document.write( "P(4) = (15)*(0.41)^(4)*(0.59)^2
\n" ); document.write( "P(4) = (15)*(0.02825761)*(0.3481)
\n" ); document.write( "P(4) = 0.147547110615
\n" ); document.write( "The probability that exactly 4 people use their phone during meetings or in class is roughly 0.147547110615\r
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\n" ); document.write( "\n" ); document.write( "Repeat similar steps for x = 5 and x = 6
\n" ); document.write( "I'll skip the steps and jump to the results of each
\n" ); document.write( "P(5) = 0.041013095154
\n" ); document.write( "P(6) = 0.004750104241\r
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\n" ); document.write( "\n" ); document.write( "Then,
\n" ); document.write( "\"P%28x+%3E=+4%29+=+P%284%29+%2B+P%285%29+%2B+P%286%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"P%28x+%3E=+4%29+=+0.147547110615%2B0.041013095154%2B0.004750104241\"\r
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\n" ); document.write( "\n" ); document.write( "\"P%28x+%3E=+4%29+=+0.19331031001\"\r
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\n" ); document.write( "\n" ); document.write( "The probability of at least 4 people, out of 6 total in the sample size, using a smartphone during meetings or class is roughly 0.19331031001
\n" ); document.write( "When rounding to something like four decimal places, we get roughly 0.1933
\n" ); document.write( "Round the answer however your teacher instructs.
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