document.write( "Question 1196851: Find the domain and range of f(x) =(x+1)^(x-1)
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Algebra.Com's Answer #829915 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "Clearly x = -1 is a critical value in determining the domain and range.

\n" ); document.write( "At x = -1, the function is

\n" ); document.write( "\"%28-1%2B1%29%5E%28-1-1%29=0%5E%28-2%29=1%2F0%5E2\"

\n" ); document.write( "which is undefined.

\n" ); document.write( "So x = -1 is not in the domain.

\n" ); document.write( "For any value of x greater than -1, the expression is a power of a positive number, so the function value can always be evaluated. So (-1, infinity) is at least part of the domain.

\n" ); document.write( "The tricky part of determining the domain is with values of x less than -1. That results in a negative number raise to a negative power.

\n" ); document.write( "A negative number raised to a negative power is a real number if and only if the power is an integer. For example...

\n" ); document.write( "\"f%28-2%29=%28-1%29%5E%28-3%29+=+1%2F%28-1%29%5E3+=+-1\"
\n" ); document.write( "\"f%28-3%29=%28-2%29%5E%28-4%29=1%2F%28-2%29%5E4=1%2F16+=+0.625\"
\n" ); document.write( "\"f%28-4%29=%28-3%29%5E%28-5%29=1%2F%28-3%29%5E5=-1%2F243=-0.0041\"

\n" ); document.write( "But for non-integer values of x less than -1, the function value is not a real number.

\n" ); document.write( "So....

\n" ); document.write( "Depending on your definition of domain, the domain of the function is either

\n" ); document.write( "(-1,infinity)

\n" ); document.write( "or

\n" ); document.write( "(-1,infinity) U {integers less than -1}

\n" ); document.write( "For the range, unless you know some very high-level mathematics, you can use a graphing calculator to find the answer. It should be clear that there is no upper limit to the range; my TI-83 calculator shows a minimum value of approximately 0.815154 at approximately x=0.454731.

\n" ); document.write( "So the range is approximately (0.815154,infinity).

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