document.write( "Question 1196866: Assume that at an actual temperature of freezing (0°C) on a batch of thermometers, the temperatures displayed are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading less than
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document.write( "0.76°C if the actual temperature is freezing (0°C).
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Algebra.Com's Answer #829896 by Theo(13342)![]() ![]() You can put this solution on YOUR website! mean is 0 \n" ); document.write( "standard deviation is 1 \n" ); document.write( "z-score = (x - m) / s \n" ); document.write( "z is the z-score \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard deviation. \n" ); document.write( "fox x = .76, the formula becomes z = (.76 - 0) / 1 = .76 \n" ); document.write( "area to the left of a z-score of .76 = .77637. \n" ); document.write( "this means that the probability of obtaining a reading less than .76 from a randomly selected thermometer = .77637 = 77.637%. \n" ); document.write( "this means that 77.637% of the thermometers in the batch of thermometers will have a reading less than .76 degrees centigrade when the actual temperature is 0 degrees centigrade. \n" ); document.write( "on the graph, the normal distribution will look like this: \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " |