document.write( "Question 1196867: Twenty-two percent of all light emitting diode (LED) displays are manufactured by Samsung. What is the probability that in a collection of two independent LED HDTV purchases, at least one is a Samsung? (Round your answer to 3 decimal places.)
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #829889 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "Twenty-two percent of all light emitting diode (LED) displays are manufactured by Samsung.
\n" ); document.write( "What is the probability that in a collection of two independent LED HDTV purchases,
\n" ); document.write( "at least one is a Samsung? (Round your answer to 3 decimal places.)
\n" ); document.write( "~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "The probability that no one of two diodes is a Samsung is  \"%281-0.22%29%5E2\" = \"0.78%5E2\" = 0.6084.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The answer to the problem's question is the COMPLEMENT to 1  \r\n" );
document.write( "\r\n" );
document.write( "      P = 1 - 0.6084 = 0.3916 = 0.392  (rounded).\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );