document.write( "Question 1196850: How many liters of a solution that is 30% alcohol must be mixed with 80 liters of a solution that is 90% alcohol to get a solution that is 60% alcohol? \n" ); document.write( "
Algebra.Com's Answer #829869 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(1) An informal solution using common sense.... \n" ); document.write( "The desired concentration, 60% is halfway between 30% and 90%; that means equal amounts of the two ingredients are needed. \n" ); document.write( "ANSWER: 80 liters \n" ); document.write( "(2) A typical setup for solving the problem using formal algebra.... \n" ); document.write( "x liters of .30 alcohol, plus 80 liters of .90 alcohol, equals (80+x) liters of .60 alcohol: \n" ); document.write( " \n" ); document.write( "Solve using basic algebra; I'll leave that to you. \n" ); document.write( "Obviously your answer should be 80 liters.... \n" ); document.write( " \n" ); document.write( " |