document.write( "Question 1196829: The length of a rectangle is 6 cm. greater than its width. If the width is 2 cm less and its
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Algebra.Com's Answer #829842 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "The length of a rectangle is 6 cm. greater than its width. If the width is 2 cm less and its
\n" ); document.write( "length is 3 cm. greater, the area would be the same as before. Find the dimensions of the
\n" ); document.write( "rectangle.
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document.write( "x     = the width\r\n" );
document.write( "(x+6) = the length.\r\n" );
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document.write( "Write equation as you read the problem\r\n" );
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document.write( "    x*(x+6) = (x-2)*((x+6)+3).\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    x*(x+6) = (x-2)*(x+9)\r\n" );
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document.write( "    x^2 + 6x = x^2 - 2x + 9x - 18\r\n" );
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document.write( "    x^2 + 6x = x^2 + 7x - 18\r\n" );
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document.write( "          6x =       7x - 18\r\n" );
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document.write( "          18 =       7x - 6x\r\n" );
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document.write( "           x =         18\r\n" );
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document.write( "ANSWER.  The dimensions of the rectangle are 18 cm and 24 cm.\r\n" );
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