document.write( "Question 1196812: A lab has a sample of ore containing 500 mg of radioactive material. The radioactive material has a half-life of one day, so it takes one day for half the atoms in the substance to decay.\r
\n" ); document.write( "\n" ); document.write( "A. Is this a geometric or arithmetic sequence?\r
\n" ); document.write( "\n" ); document.write( "B. Does it make a difference if you calculate the half-life at the beginning or end of the day? Explain.\r
\n" ); document.write( "\n" ); document.write( "C. What formula can you use to find the radioactive material in the sample at the beginning of the 7th day?
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Algebra.Com's Answer #829815 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "A. Is this a geometric or arithmetic sequence?
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\n" ); document.write( "\n" ); document.write( "Completely obvious!\r
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\n" ); document.write( "C. What formula can you use to find the radioactive material in the sample at the beginning of the 7th day?
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\n" ); document.write( "\n" ); document.write( "Initially before any time pass, 500 mg. of the radioactive material.
\n" ); document.write( "After one day (or one half-life), \"500%2A%281%2F2%29\";
\n" ); document.write( "AFTER two days (or two half-lives), \"500%2A%281%2F2%29%5E2\";
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\n" ); document.write( "AFTER some number x days (x number of half-lives), \"500%281%2F2%29%5Ex\" \"mg\" of material remaining.\r
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\n" ); document.write( "\n" ); document.write( "The beginning of day 7 is same as the end of day 6, so the amount present than would be \"500%281%2F2%29%5E6\".
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