document.write( "Question 1196798: prove that √ 2/2 + √ 2/2i is a square root of i \n" ); document.write( "
Algebra.Com's Answer #829802 by ikleyn(52777)\"\" \"About 
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document.write( "The square of the modulus of this number,  \"sqrt%282%29%2F2\" + \"%28sqrt%282%29%2F2%29%2Ai\", is\r\n" );
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document.write( "    \"r%5E2\" = \"%28sqrt%282%29%2F2%29%5E2\" + \"%28sqrt%282%29%2F2%29%5E2\" = \"2%2F4+%2B+2%2F4\" = \"1%2F2\" + \"1%2F2\" = 1.\r\n" );
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document.write( "So, the modulus itself is  r = \"sqrt%281%29\" = 1.\r\n" );
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document.write( "The argument of this number, \"a\", satisfies \r\n" );
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document.write( "    tan(a) = \"%28%28sqrt%282%29%2F2%29%29%2F%28%28sqrt%282%29%2F2%29%29\" = 1.\r\n" );
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document.write( "So, the argument is  a = \"pi%2F4\" = 45°.\r\n" );
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document.write( "Hence, the square of this number has the modulus \"1%5E2\" = 1 and the argument 2a = \"pi%2F2\" = 90°.\r\n" );
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document.write( "It means that the square of the given number is the complex imaginary unit \"i\".\r\n" );
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