document.write( "Question 1196792: A student makes a $10.50 purchase at the bookstore with a $20 bill. The store has no bills and gives a change in quarters and 50 Cent pieces. There are 30 coins and all. How many of each kind are there? \n" ); document.write( "
Algebra.Com's Answer #829795 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "If a formal algebraic solution is needed, use one like that provided in the response from the other tutor.

\n" ); document.write( "But this kind of relatively easy problem can provide good problem-solving practice and good mental exercise by solving it using logical reasoning and basic arithmetic.

\n" ); document.write( "(1) The required change is $9.50.
\n" ); document.write( "(2) If all 30 coins were quarters, that would be only $7.50, which is $2.00 short of the required total.
\n" ); document.write( "(3) Since each half dollar is worth $0.25 more than each quarter, the number of half dollars needed to make the addition $2.00 is 200/25 = 8.

\n" ); document.write( "So there were 8 half dollars, which means 30-8 = 22 quarters.

\n" ); document.write( "ANSWER: 8 half dollars; 22 quarters

\n" ); document.write( "CHECK: 8(50)+22(25) = 400+550 = 950

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