document.write( "Question 1196788: Given: segment AC bisects segment DB\r
\n" ); document.write( "\n" ); document.write( "Given: segment DB bisects segment AC\r
\n" ); document.write( "\n" ); document.write( "Given: CE = BE\r
\n" ); document.write( "\n" ); document.write( "Prove: segment AE is congruent to segment DE
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Algebra.Com's Answer #829791 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Not true --- so of course it can't be proved.

\n" ); document.write( "AC and BD bisecting each other means ABCD is a parallelogram.

\n" ); document.write( "Point E is not defined; we only know that CE=BE, which means E is somewhere on the perpendicular bisector of side BC.

\n" ); document.write( "But in the general case -- even if E is the midpoint of BC -- it is NOT true that AE and DE are congruent.

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