document.write( "Question 1196767: A survey of 52 U.S. supermarkets yielded the following relative frequency table, where X is the number of checkout lanes at a randomly chosen supermarket.
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document.write( "x 1 2 3 4 5 6 7 8 9 10
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document.write( "P(X = x)
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document.write( "0.01 0.02 0.02 0.10 0.10 0.15 0.25 0.20 0.10 0.05
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document.write( "(a)
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document.write( "Compute 𝜇 = E(X). HINT [See Example 3.]
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document.write( "E(X) =
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document.write( "Interpret the result.
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document.write( "This was the most frequently observed number of checkout lanes in surveyed supermarkets.
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document.write( "There were, on average, this many checkout lanes in a supermarket that was surveyed.
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document.write( "There were at least this many checkout lanes in each supermarket that was surveyed.
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document.write( "There were at most this many checkout lanes in each supermarket that was surveyed.\r
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document.write( "Find
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document.write( "P(X < 𝜇) or P(X > 𝜇).
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document.write( "P(x < 𝜇)
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document.write( "=
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document.write( "P(x > 𝜇)
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document.write( "=
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document.write( "Interpret the result.
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document.write( "Then
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document.write( "P(x > 𝜇)
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document.write( " is
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document.write( "greater than
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document.write( "
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document.write( ".
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document.write( "
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document.write( "P(x < 𝜇).
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document.write( " Thus, most supermarkets have
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document.write( "more than
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document.write( "
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document.write( ".
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document.write( " the average number of checkout lanes. \n" );
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Algebra.Com's Answer #829765 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I'll get you started on the first part of the question.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "𝜇 = E(X) = 6.66 is the expected value. \n" ); document.write( "There were, on average, this many checkout lanes in a supermarket that was surveyed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Work Shown:\r \n" ); document.write( "\n" ); document.write( "
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