document.write( "Question 1196740: Answer the given problem, by determining the amount of products or reactant.\r
\n" ); document.write( "\n" ); document.write( "1.Limestone (CaCo3) is decomposed by heating to quicklime (CaO) and carbon dioxide. Calculate how many grams of quicklime can be produced from 1.0 kg of limestone.\r
\n" ); document.write( "\n" ); document.write( "2.Nitrous oxide (N20) is also called \"laughing gas\". it can be prepared by the thermal decomposition of ammonium nitrate (NH4NO3). The other product is H20. a.Write a balanced equation for this reaction. B. How many grams of N20 are formed if 0.46 mole of NH4N03 is used in the reaction.
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Algebra.Com's Answer #829720 by josgarithmetic(39620)\"\" \"About 
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\n" ); document.write( "Answer the given problem, by determining the amount of products or reactant.\r
\n" ); document.write( "\n" ); document.write( "1.Limestone (CaCo3) is decomposed by heating to quicklime (CaO) and carbon dioxide. Calculate how many grams of quicklime can be produced from 1.0 kg of limestone.\r
\n" ); document.write( "\n" ); document.write( "2.Nitrous oxide (N20) is also called \"laughing gas\". it can be prepared by the thermal decomposition of ammonium nitrate (NH4NO3). The other product is H20. a.Write a balanced equation for this reaction. B. How many grams of N20 are formed if 0.46 mole of NH4N03 is used in the reaction.
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\n" ); document.write( "\n" ); document.write( "Help for question #1 only:\r
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\n" ); document.write( "\n" ); document.write( "CaCO_3, 100.0869 grams/mole
\n" ); document.write( "CaO, 56.0774 grams/mole\r
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\n" ); document.write( "\n" ); document.write( "CaCO_3 ----- > CaO + CO_2\r
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\n" ); document.write( "\n" ); document.write( "One-to-one mole relationship between the limestone and the quicklime.\r
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\n" ); document.write( "\n" ); document.write( "\"%28%281000%2A56.0774%29%2F100.0869%29%2AGRAMS%2Aquicklime\"
\n" ); document.write( "Just compute this!\r
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\n" ); document.write( "\n" ); document.write( "If you understand question #1, then you know what to do for question #2.
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