document.write( "Question 1196729: Construct a probability distribution for the sum shown on the faces when two dice, each with 7 faces, are rolled.
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Algebra.Com's Answer #829709 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is what the addition table looks like when we add values from two 7-sided dice
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The possible sums are: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "X = sum of the two 7-sided dice \n" ); document.write( "P(X) = probability of that sum showing up\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The X values range from 2 to 14 inclusive. \n" ); document.write( "The sum \"2\" shows up exactly once out of 7*7 = 49 possible outcomes. Therefore P(X) = 1/49 when X = 2 \n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then we have the sum \"3\" show up twice out of 49 possible outcomes. We write 2/49 next to 3 like so \n" ); document.write( "
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\n" ); document.write( "Optionally you could reduce 7/49 to get 1/7, but I find it's better to have all the denominators be the same.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Side note: all of the P(X) values are between 0 and 1. Also, the P(X) values sum to 1. \n" ); document.write( " \n" ); document.write( " |