document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1196713>Question 1196713</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boy Is 10 years old and his mother is 37 years old. In how many years time will the mother be twice as old as her son </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #829685 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=829685\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "While a formal algebraic solution was probably wanted, you can get good problem-solving experience and good mental exercise by solving the problem using logical reasoning and simple arithmetic.<br><BR>\n" );
document.write( "The difference in their ages is 37-10 = 27, so when the mother will be twice as old as her son their ages will be 54 and 27.  Since the mother is now 37, that will be in 54-37 = 17 years.<br><BR>\n" );
document.write( "ANSWER: 17 years<br><BR>\n" );
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