document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1196717>Question 1196717</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Craig can paint a house in 18 hours and when working with John can complete the job in 10 hours. How long should it take John to complete the job working alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #829684 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=829684\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The response from the other tutor shows a standard formal algebraic method for solving this kind of \"working together\" problem.<br><BR>\n" );
document.write( "Here is an alternative method that many students like.<br><BR>\n" );
document.write( "(1) Consider the least common multiple of the two given times: LCM(10,18) = 90.<BR>\n" );
document.write( "(2) Determine the number of houses that could be painted in 90 hours:<BR>\n" );
document.write( "Craig alone: 90/18 = 5 houses<BR>\n" );
document.write( "Craig and John together: 90/10 = 9 houses<BR>\n" );
document.write( "(3) The difference of 4 houses in 90 hours is the amount of work John could do alone.<br><BR>\n" );
document.write( "John could paint 4 houses in 90 hours, so the number of hours it would take him to paint the one house alone is 90/4 = 22.5.<br><BR>\n" );
document.write( "ANSWER: 22.5 hours<br><BR>\n" );
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