document.write( "Question 1196707: log 2 (x-2) + log 2 (x+1) = 2 \n" ); document.write( "

Algebra.Com's Answer #829672 by MathTherapy(10555) $\"\"$ $\"About$

You can put this solution on YOUR website!
log 2 (x-2) + log 2 (x+1) = 2
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This appears to be base 2, and it seems as though you need this solved for x. If so, you need to communicate better!\r\n" );
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document.write( "It'd then be: \r\n" );
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document.write( "If the above is true, then x = 3  or x = - 2, but - 2 is EXTRANEOUS, so the only solution would be: x = 3.\r\n" );
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document.write( "If the above is true, then , as the other person states!

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