document.write( "Question 113995This question is from textbook Introductory and Intermediate Algebra
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document.write( ": The Hudson River flows at a rate of 3mph. A patrol boat travels 60 miles upriver and returns in a total time of 9 hr. What is the speed of the boat in still water?\r
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document.write( "D= rt upriver - 9r = 60 still water - 3rt = 60
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document.write( "Have I set this equation up correctly? Where do I go from here? Please help me. \n" );
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Algebra.Com's Answer #82962 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! D=RT OR T=D/R \n" ); document.write( "60/(R-3)+60/(R+3)=9 \n" ); document.write( "[60(R+3)+60(R-3)]/(R-3)(R+3)=9 \n" ); document.write( "(60R+180+60R-180)/(R^2-9)=9 (THE +180 & THE -180 CANCEL OUT) \n" ); document.write( "120R/(R^2-9)=9 NOW CROSS MULTIPLY \n" ); document.write( "9R^2-81=120R \n" ); document.write( "9R^-120R-81=0 \n" ); document.write( "USING THE QUADRATIC EQUATION WE GET: \n" ); document.write( " \n" ); document.write( "R=(120+-SQRT[120^2-4*9*-81])/2*9 \n" ); document.write( "R=(120+-SQRT[14,400+2916])/18 \n" ); document.write( "R=(120+-SQRT17,316)/18 \n" ); document.write( "R=(120+-131.59)/18 \n" ); document.write( "R=(120+131.59)/18 \n" ); document.write( "R=251.59/18 \n" ); document.write( "R=13.977 MPH IS THE SPEED OF THE BOAT IN STILL WATER. \n" ); document.write( " \n" ); document.write( " |