document.write( "Question 1196666: Because it is not practical to weigh bears in the field, researchers sought to develop a model to predict a bear's weight based on its length. Here are the results for a sample:\r
\n" ); document.write( "\n" ); document.write( "Total Length (cm) Weight (kg)
\n" ); document.write( "139.0 110
\n" ); document.write( "138.0 60
\n" ); document.write( "139.0 90
\n" ); document.write( "120.5 60
\n" ); document.write( "149.0 85
\n" ); document.write( "141.0 100
\n" ); document.write( "141.0 95
\n" ); document.write( "150.0 85
\n" ); document.write( "166.0 155
\n" ); document.write( "151.5 140
\n" ); document.write( "129.5 105
\n" ); document.write( "150.0 110
\n" ); document.write( "If the bear length was instead measured in inches (there are 0.3937 inches in 1 cm) and the weight was measured in pounds (there are 2.2 pounds in one kg), then the slope of the regression line would _______.\r
\n" ); document.write( "\n" ); document.write( "Group of answer choices\r
\n" ); document.write( "\n" ); document.write( "decrease by a factor of 0.179 (0.179 = 0.3937/2.2)\r
\n" ); document.write( "\n" ); document.write( "not change\r
\n" ); document.write( "\n" ); document.write( "increase by a factor of 0.179 (0.179 = 0.3737/2.2)\r
\n" ); document.write( "\n" ); document.write( "decrease by a factor of 5.588 (5.588 = 2.2/0.3937)\r
\n" ); document.write( "\n" ); document.write( "increase by a factor of 5.588 (5.588 = 2.2/0.3937) \n" ); document.write( "

Algebra.Com's Answer #829605 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Hi\r\n" );
document.write( "LENGTH VS WEIGHT OF BEAR\r\n" );
document.write( "First listed in cm & kg, then as listed in inches & pounds\r\n" );
document.write( "139	110		54.72	242\r\n" );
document.write( "138	60		54.33	132\r\n" );
document.write( "139	90		54.72	198\r\n" );
document.write( "120.5	60		47.44	132\r\n" );
document.write( "149	85		58.66	187\r\n" );
document.write( "141	100		55.51	220\r\n" );
document.write( "141	95		55.51	209\r\n" );
document.write( "150	85		59.06	187\r\n" );
document.write( "166	155		65.35	341\r\n" );
document.write( "151.5	140		59.65	308\r\n" );
document.write( "129.5	105		50.98	231\r\n" );
document.write( "150	110		59.06	242\r\n" );
document.write( "\r\n" );
document.write( "Using Excel Function SLOPE(Ys, Xs)  FOR BOTH LISTINGS to find \r\n" );
document.write( "the slope of the regression line:							\r\n" );
document.write( "			\r\n" );
document.write( "\r\n" );
document.write( "***** 5.588(1.694) = 9.467    \r\n" );
document.write( "\r\n" );
document.write( "the slope of the regression line increases by a factor of 5.588 \r\n" );
document.write( "\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
document.write( " \r\n" );
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