document.write( "Question 1196623: Solve for all values of x in the interval [0, 2𝜋] that satisfy the equation.
\n" ); document.write( "4 sin(2x) = 4 cos(x)
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Algebra.Com's Answer #829548 by ikleyn(52813) $\"\"$ $\"About$

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\n" ); document.write( "Solve for all values of x in the interval [0, 2𝜋] that satisfy the equation.
\n" ); document.write( "4 sin(2x) = 4 cos(x)
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document.write( "4 sin(2x) = 4 cos(x)  implies, by canceling common factor \"4\" in both sides\r\n" );
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document.write( "    sin(2x) = cos(x),\r\n" );
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document.write( "    2sin(x)*cos(x) = cos(x)\r\n" );
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document.write( "    2sin(x)*cos(x) - cos(x) = 0\r\n" );
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document.write( "    cos(x)*(2sin(x) - 1) = 0\r\n" );
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document.write( "So, EITHER  cos(x) = 0,  OR  sin(x) = 1/2.\r\n" );
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document.write( "If cos(x) = 0,  then  x=   or  x= .\r\n" );
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document.write( "If sin(x) = 1/2,  then  x=   or  x=  -  = .\r\n" );
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document.write( "So, the solution to the given equation are  ,  ,  ,  .    ANSWER\r\n" );
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