document.write( "Question 1196588: A bag has 274 coins of nickels, dimes and quarters. There are twice as many nickels as quarters. If the total value of the coins was $30.3, how many nickels, dimes and quarters were there?
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Algebra.Com's Answer #829547 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "A bag has 274 coins of nickels, dimes and quarters. There are twice as many nickels as quarters. If the total value of the coins was $30.3, how many nickels, dimes and quarters were there?
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Let number of quarters be Q\r\n" );
document.write( "Then number of nickels = 2Q\r\n" );
document.write( "Also, number of dimes = 274 - Q - 2Q = 274 - 3Q\r\n" );
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document.write( "We then get the following VALUE equation: .25Q + .05(2Q) + .1(274 - 3Q) = 30.3\r\n" );
document.write( ".25Q + .1Q + 27.4 - .3Q = 30.3\r\n" );
document.write( ".25Q + .1Q - .3Q = 30.3 - 27.4\r\n" );
document.write( ".05Q = 2.9\r\n" );
document.write( "Number of quarters or \r\n" );
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document.write( "Number of nickels: 2(58) = 116   \r\n" );
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document.write( "Number of dimes: 274 - 3(58) = 274 - 174 = 100

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