document.write( "Question 1196621: If sin(x) = 1/3 and sec(y) = 13/12, where x and y lie between 0 and 𝜋/2,
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Algebra.Com's Answer #829544 by ikleyn(52879) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "If sin(x) = 1/3 and sec(y) = 13/12, where x and y lie between 0 and 𝜋/2,
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document.write( "If sin(x) = 1/3 and x lies between 0 and 𝜋/2,  then  \r\n" );
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document.write( "   cos(x) =  =  = .\r\n" );
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document.write( "If sec(y) = 13/12,  then  \r\n" );
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document.write( "   cos(y) =  = 12/13  and  sin(y) =  =  = .\r\n" );
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document.write( "sin(x-y) = sin(x)*cos(y) - cos(x)*sin(y) =  =  = \r\n" );
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document.write( "         =  = .        ANSWER\r\n" );
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