document.write( "Question 1196618: The total expenditure E of a household is partly constant and partly varies directly as the size S of the household.
\n" ); document.write( "(a) find the equation connecting E and S, if when E=300,S=5persons and E=400,S=6
\n" ); document.write( "(b) what is the total expenditure when the size of the household is 10persoms
\n" ); document.write( "(c) how many persons will consume a total expenditure of $600
\n" ); document.write( "

Algebra.Com's Answer #829540 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
if the total expenditure \"E\" of a household is partly constant and partly varies directly as the size \"S\" of the household, we have\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"E+=+a+%2B+bS+\" were \"a\" is a constant and \"b\" the number of persons\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "a) find the equation connecting \"E\" and \"S\", if when \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"E=300\",\"S=5\" persons \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"300+=+a+%2B+5b\".................solve for\"+a\"\r
\n" ); document.write( "\n" ); document.write( "\"a=300-5b\"...........eq.1\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and\"+E=400\",\"S=6\"\r
\n" ); document.write( "\n" ); document.write( "\"400+=+a+%2B+6b\".................solve for \"a\"
\n" ); document.write( "\"a=400-6b\"...........eq.2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "then from eq.1 and eq.2 we have\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"300-5b=400-6b\"..............solve for \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"6b-5b=400-300\"\r
\n" ); document.write( "\n" ); document.write( "\"b=100\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "go to\r
\n" ); document.write( "\n" ); document.write( "\"a=400-6b\"...........eq.2, substitute\"+b\"\r
\n" ); document.write( "\n" ); document.write( "\"a=400-6%2A100\"\r
\n" ); document.write( "\n" ); document.write( "\"a=400-600\"\r
\n" ); document.write( "\n" ); document.write( "\"a=+-200\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and equation is\r
\n" ); document.write( "\n" ); document.write( "\"E+=-200%2B+100S\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "b. \r
\n" ); document.write( "\n" ); document.write( "if \"S=10\"\r
\n" ); document.write( "\n" ); document.write( "\"E+=-200%2B+100%2A10=800\"\r
\n" ); document.write( "\n" ); document.write( "the total expenditure is $\"800\" when the size of the household is \"10\" persons\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "c.\r
\n" ); document.write( "\n" ); document.write( "\"E+\"= $\"600\"\r
\n" ); document.write( "\n" ); document.write( "\"600=-200%2B+100S\"\r
\n" ); document.write( "\n" ); document.write( "\"600%2B200=100S\"........divide by \"100\"\r
\n" ); document.write( "\n" ); document.write( "\"6%2B2=S\"\r
\n" ); document.write( "\n" ); document.write( "\"S=8\"\r
\n" ); document.write( "\n" ); document.write( " \"8\" persons will consume a total expenditure of $\"600\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );