document.write( "Question 113986: Bob invested $20,000, part at 14% and part at 13%. If the total interest at the end of the year is $2,720, how much did he invest at 14%? \n" ); document.write( "
Algebra.Com's Answer #82954 by BrittanyM(80)\"\" \"About 
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We can solve this by setting up a sysrem:\r
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\n" ); document.write( "\n" ); document.write( "Since we know the the total investment was 20,000, 100% of both rates is written as\r
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\n" ); document.write( "\n" ); document.write( "x + y = 20,000\r
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\n" ); document.write( "\n" ); document.write( "And since the given rates of the investment, 14% and 13%, yielded 2,720 we have\r
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\n" ); document.write( "\n" ); document.write( "0.14x + 0.13y = 2,720\r
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\n" ); document.write( "\n" ); document.write( "From the first equation, let
\n" ); document.write( "x = -y + 20,000\r
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\n" ); document.write( "\n" ); document.write( "So let's plug this into the second equation:\r
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\n" ); document.write( "\n" ); document.write( "0.14(-y + 20,000) + 0.13y = 2,720
\n" ); document.write( "-0.14y + 2,800 + 0.13y = 2,720
\n" ); document.write( "-0.01y + 2,800 = 2,720
\n" ); document.write( "-0.01y = -80
\n" ); document.write( "y = 8,000\r
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\n" ); document.write( "\n" ); document.write( "Now, we can subtract our y value from 20,000 in order to find x:\r
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\n" ); document.write( "\n" ); document.write( "x = -y + 20,000
\n" ); document.write( "x = -8,000 + 20,000
\n" ); document.write( "x = 12,000
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