document.write( "Question 1196616: The length of a rectangle is twice it's width. If the width is reduced by 1cm and the length is reduced by 2cm, the area will be 15cm². The dimensions of the original rectangle. \n" ); document.write( "

Algebra.Com's Answer #829536 by ikleyn(52794) $\"\"$ $\"About$

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document.write( "Let w be the width, in centimeters.\r\n" );
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document.write( "Then the length is 2w cm.\r\n" );
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document.write( "After changing the dimensions, they become (w-1) cm and (2w-2) cm.\r\n" );
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document.write( "The area equation is\r\n" );
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document.write( "    (w-1)*(2w-2) = 15.\r\n" );
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document.write( "Simplify and solve it MENTALLY\r\n" );
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document.write( "    2*(w-1)*(w-1) = 15\r\n" );
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document.write( "      (w-1)^2 = 15/2 = 7.5\r\n" );
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document.write( "       w-1 = \r\n" );
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document.write( "       w =  = 3.74 cm.\r\n" );
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document.write( "ANSWER.  The dimensions of the original rectangle are  3.74 cm (the width)  and  2*3.74 = 7.48 cm (the length).\r\n" );
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