document.write( "Question 1196616: The length of a rectangle is twice it's width. If the width is reduced by 1cm and the length is reduced by 2cm, the area will be 15cm². The dimensions of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #829532 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi\r\n" );
document.write( "The length of a rectangle is twice it's width.\r\n" );
document.write( "width w\r\n" );
document.write( "length 2w\r\n" );
document.write( "If the width is reduced by 1cm and the length is reduced by 2cm, \r\n" );
document.write( "the area will be 15cm².\r\n" );
document.write( "A = length*width\r\n" );
document.write( "(2w-2)(w-1) = 15cm²\r\n" );
document.write( "Solve for w, rounding answer as instructed \r\n" );
document.write( "2w^2 -4w + 2 = 15\r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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