document.write( "Question 1195923: A thin hoop of radius 0.50 m and a mass of 0.20 kg is released from rest and allowed to roll down an inclined plane. Calculate the rotational kinetic energy at the bottom if the angular speed is 2.0 rad/s at that position. [Moment of inertia of thin hoop, I = MR^2, M = mass and R = radius of hoop](2 Points)
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Algebra.Com's Answer #829506 by math_helper(2461) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "The connecting formula you need is:
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document.write( "   I will use w for ω (omega, normally this is used for angular speed), due to problems rendering...\r
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document.write( "Substituting for I:
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document.write( "  
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document.write( "= 
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document.write( "=  
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document.write( "=   Joule \n" );
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