document.write( "Question 1196562: Pls help. \r
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document.write( "Elias and Shui are good friends. This year Elias is 48 years older than Shui. Nine years
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document.write( "ago Elias was three times Shui's age. How old is Elias? \n" );
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Algebra.Com's Answer #829461 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The two responses you have received to now both show the same method of solution; that method sets up the problem starting with the statement that Elias is 48 years older than Shui. \n" ); document.write( "I would start the problem differently, resulting in easier algebra.... \n" ); document.write( "Since Elias was 3 times as old as Shui 9 years ago, let x and 3x be their ages 9 years ago. \n" ); document.write( "The difference between their ages 9 years ago is then 3x-x=2x. \n" ); document.write( "But the difference in their ages is 48 years; so 2x=48 and x=24. \n" ); document.write( "So their ages 9 years ago were x=24 and 3x=72. \n" ); document.write( "So now the age of Elias is 72+9=81. \n" ); document.write( "ANSWER: 81 \n" ); document.write( "Without all the words.... \n" ); document.write( "x = age of Shiu 9 years ago \n" ); document.write( "3x = age of Elias 9 years ago \n" ); document.write( "3x-x = 2x = 48; x = 48/2 = 24; 3x = 3(24) = 72 \n" ); document.write( "Elias's age now: 72+9 = 81 \n" ); document.write( " \n" ); document.write( " |