document.write( "Question 1196547: Terri drove for 3 hours before lunch. After lunch she drove 4 more hours and averaged 15mph more than before lunch. If her total distance was 410 miles, what was her average speed before lunch? \n" ); document.write( "

Algebra.Com's Answer #829423 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Write the total distance equation\r\n" );
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document.write( "    3B + 4*(B+15) = 410  miles  total.\r\n" );
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document.write( "where B is her average rate before lunch, in miles per hour.\r\n" );
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document.write( "Simplify the equation and find B\r\n" );
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document.write( "    3B + 4B + 60 = 410\r\n" );
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document.write( "      7B         = 410 - 60\r\n" );
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document.write( "      7B         =   350\r\n" );
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document.write( "       B         =   350/7 = 50.\r\n" );
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document.write( "ANSWER.  Terri's average rate before lunch was 50 miles per hour.\r\n" );
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