document.write( "Question 1196537: Let U = {q, r, s, t, u, v, w, x, y, z}, A = {q, s, u, w, y}, B = {q, s, y, z}, and C = {v, w, x, y, z}. List the elements in the following set.\r
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document.write( "A ∩ B with line on top \n" );
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Algebra.Com's Answer #829418 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There's ambiguity when you mention \"with a line on top\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Is the line solely over the B? Or is it over everything?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Do you mean \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Or do you mean \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll go over each interpretation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's focus on \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The universal set is \n" ); document.write( "U = {q, r, s, t, u, v, w, x, y, z} \n" ); document.write( "Cross off the stuff you find in set B \n" ); document.write( "So we'll cross off: q, s, y, and z \n" ); document.write( "This forms the set B' which is the same as writing \n" ); document.write( "B' = {r, t, u, v, w, x} \n" ); document.write( "This is the complement of set B.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Stuff in B' is not found in B, and vice versa. \n" ); document.write( "They are complete opposite of one another. \n" ); document.write( "The two sets union together to form the universal set.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Think of it like this: \n" ); document.write( "stuff inside B is inside a house \n" ); document.write( "stuff outside B is outside the house\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we'll intersect the set A with set B' \n" ); document.write( "A = {q, s, u, w, y} \n" ); document.write( "B' = {r, t, u, v, w, x} \n" ); document.write( "We see that the letters u and w are inside both A and B' at the same time. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence A ∩ B' = {u, w} \n" ); document.write( "which is the same as saying \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now onto \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is the same as writing (A ∩ B)' \n" ); document.write( "We're taking the complement of set (A ∩ B)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here are sets A and B \n" ); document.write( "A = {q, s, u, w, y} \n" ); document.write( "B = {q, s, y, z} \n" ); document.write( "which means, \n" ); document.write( "A ∩ B = {q, s, y} \n" ); document.write( "since those three letters are found in both sets\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We'll delete q,s,y from the universal set \n" ); document.write( "U = {q, r, s, t, u, v, w, x, y, z} \n" ); document.write( "(A ∩ B)' = { \n" ); document.write( "(A ∩ B)' = {r, t, u, v, w, x, z}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |