document.write( "Question 1196537: Let U = {q, r, s, t, u, v, w, x, y, z}, A = {q, s, u, w, y}, B = {q, s, y, z}, and C = {v, w, x, y, z}. List the elements in the following set.\r
\n" ); document.write( "\n" ); document.write( "A ∩ B with line on top
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Algebra.Com's Answer #829418 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "There's ambiguity when you mention \"with a line on top\"\r
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\n" ); document.write( "\n" ); document.write( "Is the line solely over the B? Or is it over everything?\r
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\n" ); document.write( "\n" ); document.write( "Do you mean \r
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\n" ); document.write( "\n" ); document.write( "Or do you mean \r
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\n" ); document.write( "\n" ); document.write( "I'll go over each interpretation.\r
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\n" ); document.write( "\n" ); document.write( "Let's focus on \r
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\n" ); document.write( "\n" ); document.write( "The universal set is
\n" ); document.write( "U = {q, r, s, t, u, v, w, x, y, z}
\n" ); document.write( "Cross off the stuff you find in set B
\n" ); document.write( "So we'll cross off: q, s, y, and z
\n" ); document.write( "This forms the set B' which is the same as writing
\n" ); document.write( "B' = {r, t, u, v, w, x}
\n" ); document.write( "This is the complement of set B.\r
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\n" ); document.write( "\n" ); document.write( "Stuff in B' is not found in B, and vice versa.
\n" ); document.write( "They are complete opposite of one another.
\n" ); document.write( "The two sets union together to form the universal set.\r
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\n" ); document.write( "\n" ); document.write( "Think of it like this:
\n" ); document.write( "stuff inside B is inside a house
\n" ); document.write( "stuff outside B is outside the house\r
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\n" ); document.write( "\n" ); document.write( "Now we'll intersect the set A with set B'
\n" ); document.write( "A = {q, s, u, w, y}
\n" ); document.write( "B' = {r, t, u, v, w, x}
\n" ); document.write( "We see that the letters u and w are inside both A and B' at the same time. \r
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\n" ); document.write( "\n" ); document.write( "Hence A ∩ B' = {u, w}
\n" ); document.write( "which is the same as saying \r
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\n" ); document.write( "\n" ); document.write( "Now onto \r
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\n" ); document.write( "\n" ); document.write( "This is the same as writing (A ∩ B)'
\n" ); document.write( "We're taking the complement of set (A ∩ B)\r
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\n" ); document.write( "\n" ); document.write( "Here are sets A and B
\n" ); document.write( "A = {q, s, u, w, y}
\n" ); document.write( "B = {q, s, y, z}
\n" ); document.write( "which means,
\n" ); document.write( "A ∩ B = {q, s, y}
\n" ); document.write( "since those three letters are found in both sets\r
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\n" ); document.write( "\n" ); document.write( "We'll delete q,s,y from the universal set
\n" ); document.write( "U = {q, r, s, t, u, v, w, x, y, z}
\n" ); document.write( "(A ∩ B)' = {q, r, s, t, u, v, w, x, y, z}
\n" ); document.write( "(A ∩ B)' = {r, t, u, v, w, x, z}\r
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\n" ); document.write( "\n" ); document.write( "Therefore,
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