document.write( "Question 1196534: A marketing research company is estimating which of two soft drinks college students prefer. A random sample of 100 college students produced the following 95% confidence interval for the proportion of college students who prefer drink A: (0.262, 0.622). What would happen to the confidence interval if the confidence level were changed to 90%?\r
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document.write( "There would be no change in the width of the interval.\r
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document.write( "The interval would get narrower.\r
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document.write( "The interval would get wider.\r
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document.write( "It is impossible to tell until the 90% interval is constructed \n" );
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Algebra.Com's Answer #829413 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: B) The interval would get narrower.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "============================================================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The margin of error formula for proportions is \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n) \n" ); document.write( "where, \n" ); document.write( "z = critical value based on the confidence level \n" ); document.write( "phat = sample proportion \n" ); document.write( "n = sample size\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We'll fix phat and n to be constant \n" ); document.write( "They won't change in value.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's say phat = 0.50 and n = 100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At 95% confidence, the z critical value is roughly 1.96 \n" ); document.write( "At 90% confidence, the z critical value is roughly 1.645 \n" ); document.write( "Use a table like this \n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf \n" ); document.write( "to get those values. Look at the bottom row labeled \"Z\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Compute the value of E for the 95% confidence level \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n) \n" ); document.write( "E = 1.96*sqrt(0.50*(1-0.50)/100) \n" ); document.write( "E = 0.098\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now do the same for the 90% confidence level. \n" ); document.write( "Keep phat and n the same from earlier. \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n) \n" ); document.write( "E = 1.645*sqrt(0.50*(1-0.50)/100) \n" ); document.write( "E = 0.08225\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The margin of error has gone from 0.098 to 0.08225 \n" ); document.write( "The margin of error decreases when the confidence level decreases. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This makes the confidence interval get more narrow. \n" ); document.write( "The confidence interval has the width of 2*E, so we can think of E as the radius of the confidence interval.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's an alternative way to think about it:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's say your friend drew out a number line, and marked it from 1 to 10 including both endpoints. \n" ); document.write( "Then your friend picked one of the numbers on that number line. \n" ); document.write( "Your goal is to guess their number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You are 100% confident it is somewhere between 1 and 10. \n" ); document.write( "This is the largest confidence interval possible, and hence the widest width possible along the number line.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you lowered the confidence down to 90%, then you could have a subinterval of say from 2 to 10, or something along those lines. \n" ); document.write( "The friend's number may be in this range, but you aren't fully certain. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then an 80% confidence interval could be going from 3 to 10 as one possible subinterval. The level of uncertainty has dropped further.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Each time the confidence decreases, the interval shrinks.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Similar question: \n" ); document.write( "https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1196535.html \n" ); document.write( " \n" ); document.write( " |