document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1196537>Question 1196537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let U = {q, r, s, t, u, v, w, x, y, z}, A = {q, s, u, w, y}, B = {q, s, y, z}, and C = {v, w, x, y, z}. List the elements in the following set.\r<BR>\n" );
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document.write( "A ∩ B with line on top </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #829407 by </B><A HREF=/tutors/aboutme.mpl?userid=MathLover1><B>MathLover1(20850)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathLover1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathLover1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=829407\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "A ∩ B with line on top\r<BR>\n" );
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document.write( " First, A ∩ B is equal to the set that contains elements common to both A and B. The  line on top means “complement” (all the objects that do not belong to set A∩ B), and you can write it as (A ∩ B)’  or (A ∩ B)^c\r<BR>\n" );
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document.write( "to find (A ∩ B)’ , first find A ∩ B (elements common to both A and B)\r<BR>\n" );
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document.write( "if A = {q, s, u, w, y} and B = {q, s, y, z}\r<BR>\n" );
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document.write( "A ∩ B={q, s, y}\r<BR>\n" );
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document.write( "now find complement (A ∩ B)’  (all the objects in set U that do not belong to set A∩ B)\r<BR>\n" );
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document.write( "(A ∩ B)’={ r,  t, u, v, w, x,  z}  => your answer\r<BR>\n" );
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