document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1196511>Question 1196511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 8x=3y=7z, find x:y:z </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #829403 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=829403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "I have no idea what tutor @josgarithmetic was doing to solve the problem; in any case, his answer does not satisfy the given conditions.<br><BR>\n" );
document.write( "Here are a few ways you can solve this kind of problem.<br><BR>\n" );
document.write( "(1) Choose any value for one variable and use the given ratios to find the corresponding values of the other two.  Then make a ratio of the three values, and convert the ratio to whole numbers if needed.<br><BR>\n" );
document.write( "y = 1 --> x=3/8; z = 3/7<BR>\n" );
document.write( "the ratio x:y:z is (3/8):1:(3/7) = 21:56:24<br><BR>\n" );
document.write( "(2) Given 8x, 3y, and 7z all equal to the same number, let that number be the LCM of the three coefficients: 8*3*7 = 168.  Then<BR>\n" );
document.write( "x = 168/8 = 21; y = 168/3 = 56; z = 168/7 = 24<BR>\n" );
document.write( "and the ratio is again x:y:z = 21:56:24<br><BR>\n" );
document.write( "(3) Having observed how solution method (2) works, you should be able to see that the solution is simply<BR>\n" );
document.write( "x:y:z = (3*7):(8*7):(8*3) = 21:56:24<br><BR>\n" );
document.write( " </SPAN>\n" );
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