document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=113975>Question 113975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive integers such that the sum of the first two integers is 24 more than the third integer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #82940 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=82940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET X, X+1 & X+2 BE THE THREE CONSECUTIVE INTEGERS.<BR>\n" );
document.write( "X+(X+1)=24+(X+2)<BR>\n" );
document.write( "2X+1=24+X+2<BR>\n" );
document.write( "2X-X=24+2-1<BR>\n" );
document.write( "X=25 ANSWER FOR THE FIRST INTEGER.<BR>\n" );
document.write( "25+1=26 FOR THE SECOND<BR>\n" );
document.write( "25+2=27 FOR THE THIRD.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "25+26=24+27<BR>\n" );
document.write( "51=51<BR>\n" );
document.write( " <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );