document.write( "Question 1196517: A bag contains five balls, numbered 1, 2, 3, 4 and 5. Another bag contains six balls numbered
\n" ); document.write( "1, 2, 3, 4, 5 and 6. One ball is drawn at random from each bag. Find the probability that
\n" ); document.write( "a) one ball is numbered 1 and the other 6,
\n" ); document.write( "b) both balls have an odd number,
\n" ); document.write( "(c) both balls have the same number,
\n" ); document.write( "(d) the sum of the numbers on the balls is 9.
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Algebra.Com's Answer #829398 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "There are 5 choices for the ball from the first bag and 6 choices for the ball from the second bag. So the number of possible draws is 5*6 = 30; that is the denominator of all the probability fractions.

\n" ); document.write( "(a) one ball is numbered 1, the other 6. The 6 had to come from the second bag, so the 1 had to come from the first.
\n" ); document.write( "Number of favorable outcomes: 1*1 = 1; probability 1/30

\n" ); document.write( "(b) both balls have an odd number. 3 possibilities from each bag.
\n" ); document.write( "Number of favorable outcomes: 3*3 = 9; probability 9/30

\n" ); document.write( "(c) both balls have the same number. That number can be 1, 2, 3, 4, or 5.
\n" ); document.write( "Number of favorable outcomes: 5; probability 5/30

\n" ); document.write( "(d) the sum of the numbers on the ball is 9. The combination can be 3+6, 4+5, or 5+4.
\n" ); document.write( "Number of favorable outcomes: 3; probability 3/30

\n" ); document.write( "ANSWERS:
\n" ); document.write( "(a) 1/30
\n" ); document.write( "(b) 9/30 = 3/10
\n" ); document.write( "(c) 5/30 = 1/6
\n" ); document.write( "(d) 3/30 = 1/10

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