document.write( "Question 1196517: A bag contains five balls, numbered 1, 2, 3, 4 and 5. Another bag contains six balls numbered
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document.write( "1, 2, 3, 4, 5 and 6. One ball is drawn at random from each bag. Find the probability that
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document.write( "a) one ball is numbered 1 and the other 6,
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document.write( "b) both balls have an odd number,
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document.write( "(c) both balls have the same number,
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document.write( "(d) the sum of the numbers on the balls is 9. \n" );
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Algebra.Com's Answer #829398 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There are 5 choices for the ball from the first bag and 6 choices for the ball from the second bag. So the number of possible draws is 5*6 = 30; that is the denominator of all the probability fractions. \n" ); document.write( "(a) one ball is numbered 1, the other 6. The 6 had to come from the second bag, so the 1 had to come from the first. \n" ); document.write( "Number of favorable outcomes: 1*1 = 1; probability 1/30 \n" ); document.write( "(b) both balls have an odd number. 3 possibilities from each bag. \n" ); document.write( "Number of favorable outcomes: 3*3 = 9; probability 9/30 \n" ); document.write( "(c) both balls have the same number. That number can be 1, 2, 3, 4, or 5. \n" ); document.write( "Number of favorable outcomes: 5; probability 5/30 \n" ); document.write( "(d) the sum of the numbers on the ball is 9. The combination can be 3+6, 4+5, or 5+4. \n" ); document.write( "Number of favorable outcomes: 3; probability 3/30 \n" ); document.write( "ANSWERS: \n" ); document.write( "(a) 1/30 \n" ); document.write( "(b) 9/30 = 3/10 \n" ); document.write( "(c) 5/30 = 1/6 \n" ); document.write( "(d) 3/30 = 1/10 \n" ); document.write( " \n" ); document.write( " |